通过这种曲线可以看到一种由8到0的过度

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#http://www.mathcurve.com/courbes2d/cassini/cassini.shtmlvertices = 1000t = from (-PI) to (PI)a = 10b = rand2(0, 4*a)e = b/a;p = a*sqrt(cos(2*t) + sqrt(e^4 - sin(2*t)^2))x = p*cos(t)y = p*sin(t)

面:

vertices = D1:512 D2:100u = from (-PI) to (PI) D1v = from (0) to (4) D2a = 10p = a*sqrt(cos(2*u) + sqrt(v^4 - sin(2*u)^2))x = p*cos(u)y = p*sin(u)